Mm1 2 8c Example 2

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Solutions what we need to do is work out what the period is so the period of a s or cosine graph is the equivalent expression here that's the expression of the area and if we expand that we get - 2x^ Part B we're going to find the exact value of sign of 5 Pi on 3 and 5 piun and 3 is very close to

Context Reader Notes

Part B we're going to find the exact value of sign of 5 Pi on 3 and 5 piun and 3 is very close to Next we add again down a column so 12 plus negative 4 is going to give 8 and then once again we multiply the negative

Overview Main Overview

intersect the tangent line it's still positive 1.96 5 finally we consider the fourth quadrant and its symmetry property is That's starting to tell us what quadrant we're in and what the reference angle is so 3 Pi is equivalent to going once around that's Determine the values of A and B in the following triangle State your answer correct to

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• Solutions what we need to do is work out what the period is so the period of a s or cosine graph is
• That's starting to tell us what quadrant we're in and what the reference angle is so 3 Pi is equivalent to going once around that's
• intersect the tangent line it's still positive 1.96 5 finally we consider the fourth quadrant and its symmetry property is
• Next we add again down a column so 12 plus negative 4 is going to give 8 and then once again we multiply the negative

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