Mm1 2 10d Example 1

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the gradient of that line so the gradient of our tangent line is going to be wide to subtract y1 over x2 subtract X For the graph on the grid below approximate the instantaneous rate of change at x equals

General Info Guide

0.15 this will just help to simplify the equation we're trying to solve so we'll get positive t^ Simplify each of the following expressions involving logarithms so Part A we have

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Main details to review

• the gradient of that line so the gradient of our tangent line is going to be wide to subtract y1 over x2 subtract X
• For the graph on the grid below approximate the instantaneous rate of change at x equals
• 0.15 this will just help to simplify the equation we're trying to solve so we'll get positive t^
• Simplify each of the following expressions involving logarithms so Part A we have

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