Useful Summary: All right in this problem uh we have a particle that's going along this path uh defined by y equals uh 5x^ r's and thetas and things of that nature and you start recognizing oh hey this is going to be polar
Dynamics 2nd Law Rectangular Coordinates Example 1 - General Summary
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General Summary
have to figure out what that acceleration is in order to apply the um the F Newton determine and i can calculate the acceleration equals negative 16.1 feet per
Important Context for Readers
Okay in this problem we've got a non-linear spring so we're not going to follow hooke's All right in this problem uh we have a particle that's going along this path uh defined by y equals uh 5x^ r's and thetas and things of that nature and you start recognizing oh hey this is going to be polar
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- All right in this problem uh we have a particle that's going along this path uh defined by y equals uh 5x^
- Okay in this problem we've got a non-linear spring so we're not going to follow hooke's
- determine and i can calculate the acceleration equals negative 16.1 feet per
- have to figure out what that acceleration is in order to apply the um the F Newton
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